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RIOPLATENSE 1993 Problem 6

    Let ABCDEABCDE be pentagon such that AE=EDAE = ED and BC=CDBC = CD . It is known that ∠BAE+∠EDC+∠CBA=360o\angle BAE + \angle EDC + \angle CB A = 360^o and that PP is the midpoint of ABAB . Show that the triangle ECPECP is right.

    Dataset text AI-MO AoPS. Quoted with source.

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