olymmath

Putnam 2003

William Lowell Putnam Mathematical Competition 2003.

Session A

A1

  • Session A

Let nn be a fixed positive integer. How many ways are there to write nn as a sum of positive integers, n=a1+a2+⋯+ak,n = a_1 + a_2 + \cdots + a_k, with kk an arbitrary positive integer and a1≤a2≤⋯≤ak≤a1+1a_1 \le a_2 \le \cdots \le a_k \le a_1 + 1? For example, with n=4n=4 there are four ways: 4, 2+2, 1+1+2, 1+1+1+1.

Answer, solutions and source

A2

  • Session A

Let a1,a2,…,ana_1, a_2, \ldots, a_n and b1,b2,…,bnb_1, b_2, \ldots, b_n be nonnegative real numbers. Show that (a1a2⋯an)1/n+(b1b2⋯bn)1/n≤[(a1+b1)(a2+b2)⋯(an+bn)]1/n.(a_1a_2\cdots a_n)^{1/n} + (b_1b_2\cdots b_n)^{1/n} \leq \left[(a_1 + b_1)(a_2 + b_2)\cdots(a_n + b_n)\right]^{1/n}.

Answer, solutions and source

A3

  • Session A

Find the minimum value of ∣sin⁡x+cos⁡x+tan⁡x+cot⁡x+sec⁡x+csc⁡x∣| \sin x + \cos x + \tan x + \cot x + \sec x + \csc x | for real numbers xx.

Answer, solutions and source

A4

  • Session A

Suppose that a,b,c,A,B,Ca, b, c, A, B, C are real numbers, a≠0a \neq 0 and A≠0A \neq 0, such that ∣ax2+bx+c∣≤∣Ax2+Bx+C∣|ax^2 + bx + c| \leq |Ax^2 + Bx + C| for all real numbers xx. Show that ∣b2−4ac∣≤∣B2−4AC∣.|b^2 - 4ac| \leq |B^2 - 4AC|.

Answer, solutions and source

A5

  • Session A

A Dyck nn-path is a lattice path of nn upsteps (1,1)(1,1) and nn downsteps (1,−1)(1,-1) that starts at the origin OO and never dips below the xx-axis. A return is a maximal sequence of contiguous downsteps that terminates on the xx-axis. For example, the Dyck 5-path illustrated has two returns, of length 3 and 1 respectively. Show that there is a one-to-one correspondence between the Dyck nn-paths with no return of even length and the Dyck (n−1)(n-1)-paths.

Answer, solutions and source

A6

  • Session A

For a set SS of nonnegative integers, let rS(n)r_S(n) denote the number of ordered pairs (s1,s2)(s_1, s_2) such that s1∈Ss_1 \in S, s2∈Ss_2 \in S, s1≠s2s_1 \ne s_2, and s1+s2=ns_1 + s_2 = n. Is it possible to partition the nonnegative integers into two sets AA and BB in such a way that rA(n)=rB(n)r_A(n) = r_B(n) for all nn ?

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Session B

B1

  • Session B

Do there exist polynomials a(x),b(x),c(y),d(y)a(x), b(x), c(y), d(y) such that 1+xy+x2y2=a(x)c(y)+b(x)d(y)1 + x y + x^2 y^2 = a(x) c(y) + b(x) d(y) holds identically?

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B2

  • Session B

Let nn be a positive integer. Starting with the sequence 1,12,13,…,1n1, \frac{1}{2}, \frac{1}{3}, \dots, \frac{1}{n}, form a new sequence of n−1n-1 entries 34,512,…,2n−12n(n−1)\frac{3}{4}, \frac{5}{12}, \dots, \frac{2n-1}{2n(n-1)} by taking the averages of two consecutive entries in the first sequence. Repeat the averaging of neighbors on the second sequence to obtain a third sequence of n−2n-2 entries, and continue until the final sequence produced consists of a single number xnx_n. Show that xn<2/nx_n < 2/n.

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B3

  • Session B

Show that for each positive integer n, n!=∏i=1nlcm{1,2,…,⌊n/i⌋}.n! = \prod_{i=1}^n \mathrm{lcm}\{1, 2, \dots, \lfloor n/i\rfloor\} . (Here lcm\mathrm{lcm} denotes the least common multiple, and ⌊x⌋\lfloor x \rfloor denotes the greatest integer ≤x\leq x.)

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B4

  • Session B

Let f(z)=az4+bz3+cz2+dz+e=a(z−r1)(z−r2)(z−r3)(z−r4)f(z) = az^4 + bz^3 + cz^2 + dz + e = a(z - r_1)(z - r_2)(z - r_3)(z - r_4) where a,b,c,d,ea, b, c, d, e are integers, a≠0a \neq 0. Show that if r1+r2r_1 + r_2 is a rational number and r1+r2≠r3+r4r_1 + r_2 \neq r_3 + r_4, then r1r2r_1r_2 is a rational number.

Answer, solutions and source

B5

  • Session B

Let A,BA,B, and CC be equidistant points on the circumference of a circle of unit radius centered at OO, and let PP be any point in the circle's interior. Let a,b,ca, b, c be the distance from PP to A,B,CA, B, C, respectively. Show that there is a triangle with side lengths a,b,ca, b, c, and that the area of this triangle depends only on the distance from PP to OO.

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B6

  • Session B

Let f(x)f(x) be a continuous real-valued function defined on the interval [0,1][0,1]. Show that ∫01∫01∣f(x)+f(y)∣dxdy≥∫01∣f(x)∣dx.\int_0^1 \int_0^1 | f(x) + f(y) | dx dy \geq \int_0^1 |f(x)| dx.

Answer, solutions and source