Putnam 2003 B4 Session B Let f(z)=az4+bz3+cz2+dz+e=a(z−r1)(z−r2)(z−r3)(z−r4)f(z) = az^4 + bz^3 + cz^2 + dz + e = a(z - r_1)(z - r_2)(z - r_3)(z - r_4)f(z)=az4+bz3+cz2+dz+e=a(z−r1)(z−r2)(z−r3)(z−r4) where a,b,c,d,ea, b, c, d, ea,b,c,d,e are integers, a≠0a \neq 0a=0. Show that if r1+r2r_1 + r_2r1+r2 is a rational number and r1+r2≠r3+r4r_1 + r_2 \neq r_3 + r_4r1+r2=r3+r4, then r1r2r_1r_2r1r2 is a rational number. Dataset text Putnam 1995 to 2025. Quoted with source. Solutions No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label. Add a solution PreviousB3 NextB5 Locator putnam/2003/b4 · Tag PP05SG6BZZ · Edit this page on GitHub · Keys: j next, k previous