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Putnam 1958 A5

  • Session A
  1. Show that the integral equation f(x,y)=1+∫0x∫0yf(u,v)dudvf(x, y)=1+\int_{0}^{x} \int_{0}^{y} f(u, v) d u d v has at most one solution continuous for 0≤x≤1,0≤y≤10 \leq x \leq 1,0 \leq y \leq 1.

Dataset text PutnamGAP. Quoted with source.

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