olymmath

Putnam 1953 B3

  • Session B

Solve the equations dydx=z(y+z)n,  dzdx=y(y+z)n,\frac{dy}{dx}=z(y+z)^n, \; \frac{dz}{dx} = y(y+z)^n, given the initial conditions y=1y=1 and z=0z=0 when x=0.x=0.

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