olymmath

Putnam 1941 B6

  • Session B

Assuming that f(x)f(x) is continuous in the interval (0,1)(0,1) , prove that ∫x=0x=1∫y=xy=1∫z=xz=yf(x)f(y)f(z)dzdydx=16(∫01f(t)dt)3.\int_{x=0}^{x=1} \int_{y=x}^{y=1} \int_{z=x}^{z=y} f(x)f(y)f(z) dz dy dx= \frac{1}{6}\left(\int_{0}^{1} f(t) dt\right)^{3}.

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