olymmath

Putnam 1941

William Lowell Putnam Mathematical Competition 1941.

Session A

A1

  • Session A

Prove that the polynomial (a−x)6−3a(a−x)5+52a2(a−x)4−12a4(a−x)2(a-x)^6 -3a(a-x)^5 +\frac{5}{2} a^2 (a-x)^4 -\frac{1}{2} a^4 (a-x)^2 takes only negative values for 0<x<a0<x<a .

Answer, solutions and source

A2

  • Session A

Find the nn -th derivative with respect to xx of ∫0x(1+x−t1!+(x−t)22!+…+(x−t)n−1(n−1)!)entdt.\int_{0}^{x} \left(1+\frac{x-t}{1!}+\frac{(x-t)^{2}}{2!}+\ldots+\frac{(x-t)^{n-1}}{(n-1)!}\right)e^{nt} dt.

Answer, solutions and source

A3

  • Session A

A circle of radius aa rolls in the plane along the xx -axis. Show that the envelope of a diameter is a cycloid, coinciding with the cycloid traced out by a point on the circumference of a circle of diameter aa , likewise rolling in the plane along the xx -axis.

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A4

  • Session A

Let the roots a,b,ca,b,c of f(x)=x3+px2+qx+rf(x)=x^3 +p x^2 + qx+r be real, and let a≤b≤ca\leq b\leq c . Prove that f′(x)f'(x) has a root in the interval [b+c2,b+2c3]\left[\frac{b+c}{2}, \frac{b+2c}{3}\right] . What will be the form of f(x)f(x) if the root in question falls at either end of the interval?

Answer, solutions and source

A5

  • Session A

The line LL is parallel to the plane y=zy=z and meets the parabola 2x=y2,z=02x=y^2 ,z=0 and the parabola 3x=z2,y=03x=z^2, y=0 . Prove that if LL moves freely subject to these constraints then it generates the surface x=(y−z)(y2−z3)x=(y-z)\left(\frac{y}{2}-\frac{z}{3}\right) .

Answer, solutions and source

A6

  • Session A

If the xx -coordinate x‾\overline{x} of the center of mass of the area lying between the xx -axis and the curve y=f(x)y=f(x) with f(x)>0f(x)>0 , and between the lines x=0x=0 and x=ax=a is given by x‾=g(a),\overline{x}=g(a), show that f(x)=A⋅g′(x)(x−g(x))2⋅e∫1t−g(t)dt,f(x)=A\cdot \frac{g'(x)}{(x-g(x))^{2}} \cdot e^{\int \frac{1}{t-g(t)} dt}, where AA is a positive constant.

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Session B

B1

  • Session B

A particle (x,y)(x,y) moves so that its angular velocities about (1,0)(1,0) and (−1,0)(-1,0) are equal in magnitude but opposite in sign. Prove that y(x2+y2+1)dx=x(x2+y2−1)dy,y(x^2 +y^2 +1) dx= x(x^2 +y^2 -1) dy, and verify that this is the differential equation of the family of rectangular hyperbolas passing through (1,0)(1,0) and (−1,0)(-1,0) and having the origin as center.

Answer, solutions and source

B2

  • Session B

Find (i) lim⁡n→∞∑i=1n1n2+i2\lim_{n\to \infty} \sum_{i=1}^{n} \frac{1}{\sqrt{n^2 +i^{2}}} . (ii) lim⁡n→∞∑i=1n1n2+i\lim_{n\to \infty} \sum_{i=1}^{n} \frac{1}{\sqrt{n^2 +i}} . (iii) lim⁡n→∞∑i=1n21n2+i\lim_{n\to \infty} \sum_{i=1}^{n^{2}} \frac{1}{\sqrt{n^2 +i}} .

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B3

  • Session B

Let y1y_1 and y2y_2 be two linearly independent solutions of the equation y′′+P(x)y′+Q(x)=0.y''+P(x)y'+Q(x)=0. Find the differential equation satisfied by the product z=y1y2z=y_1 y_2 .

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B4

  • Session B

Given two perpendicular diameters ABAB and CDCD of an ellipse, we say that the diameter A′B′A'B' is conjugate to ABAB if A′B′A'B' is parallel to the tangent to the ellipse at AA . Let A′B′A'B' be conjugate to ABAB and C′D′C'D' be conjugate to CDCD . Prove that the rectangular hyperbola through A′,B′,C′A', B', C' and D′D' passes through the foci of the ellipse.

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B5

  • Session B

A car is being driven so that its wheels, all of radius aa feet, have an angular velocity of ω\omega radians per second. A particle is thrown off from the tire of one of these wheels, where it is supposed that aω2>ga \omega^{2} >g . Neglecting the resistance of the air, show that the maximum height above the roadway which the particle can reach is (aω+gω−1)22g.\frac{(a \omega+g \omega^{-1})^{2}}{2g}.

Answer, solutions and source

B6

  • Session B

Assuming that f(x)f(x) is continuous in the interval (0,1)(0,1) , prove that ∫x=0x=1∫y=xy=1∫z=xz=yf(x)f(y)f(z)dzdydx=16(∫01f(t)dt)3.\int_{x=0}^{x=1} \int_{y=x}^{y=1} \int_{z=x}^{z=y} f(x)f(y)f(z) dz dy dx= \frac{1}{6}\left(\int_{0}^{1} f(t) dt\right)^{3}.

Answer, solutions and source