olymmath

OPM 1994 Problem 3

  • Final day 1

Proce that number 11...11⏟2n digits−22...22⏟n digits\underbrace{11...11}_{2n \, digits}-\underbrace{22 ... 22}_{n \, digits} is, for every natural nn , a perfect square.

Dataset text AI-MO AoPS. Quoted with source.

Official text: Portuguese Mathematical Olympiad 1994 official paper, page 1.

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