olymmath

JBMO 1998 Problem 1

  • Paper

Prove that the number 111…11⏟199722…22⏟19985\underbrace{111\ldots 11}_{1997}\underbrace{22\ldots 22}_{1998}5 (which has 1997 of 1-s and 1998 of 2-s) is a perfect square.

Dataset text AI-MO AoPS. Quoted with source.

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