olymmath

PAMO 2023 Problem 1

  • Day 1

In a triangle ABCABC with AB<ACAB<AC , DD is a point on segment ACAC such that BD=CDBD = CD . A line parallel to BDBD meets segment BCBC at EE and line ABAB at FF . Point GG is the intersection of AEAE and BDBD . Show that ∠BCG=∠BCF\angle BCG = \angle BCF . (Côte d'Ivoire)

Dataset text AI-MO AoPS. Quoted with source.

Official text: Pan-African Mathematics Olympiad 2023 official paper, page 1.

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