RU-ALLRUSSIAN 1968 Problem 10
- Answer
Given a triangle ABC, and D on the segment AB, E on the segment AC, such that AD = DE = AC, BD = AE, and DE is parallel to BC. Prove that BD equals the side of a regular 10- gon inscribed in a circle with radius AC.
Dataset text NuminaMath olympiads. Quoted with source.
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BD = 2 \text{AC} \sin \pi /10
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