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OMM 1997 Problem 2

    In a triangle ABC,PABC, P and P′P' are points on side BC,QBC, Q on side CACA , and RR on side ABAB , such that ARRB=BPPC=CQQA=CP′P′B\frac{AR}{RB}=\frac{BP}{PC}=\frac{CQ}{QA}=\frac{CP'}{P'B} . Let GG be the centroid of triangle ABCABC and KK be the intersection point of AP′AP' and RQRQ . Prove that points P,G,KP,G,K are collinear.

    Dataset text AI-MO AoPS. Quoted with source.

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