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MK-MO 1996 Problem 1

    Let ABCDABCD be a parallelogram which is not a rectangle and EE be the point in its plane such that AE⊥ABAE \perp AB and CE⊥CBCE \perp CB . Prove that ∠DEA=∠CEB\angle DEA = \angle CEB .

    Dataset text AI-MO AoPS. Quoted with source.

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