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CONO-SUR 1992 Problem 5

    In a △ABC\triangle {ABC} , consider a point EE in BCBC such that AE⊥BCAE \perp BC . Prove that AE=bc2rAE=\frac{bc}{2r} , where rr is the radio of the circle circumscripte, b=ACb=AC and c=ABc=AB .

    Dataset text AI-MO AoPS. Quoted with source.

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