olymmath

OMCPLP 2021

Lusophon Mathematical Olympiad 2021.

Day 1

Problem 1

  • Day 1

Juca has decided to call all positive integers with 8 digits as sextalternadossextalternados if it is a multiple of 30 and its consecutive digits have different parity. At the same time, Carlos decided to classify all sextalternadossextalternados that are multiples of 12 as supersextalternadossuper sextalternados .

a) Show that supersextalternadossuper sextalternados numbers don't exist.

b) Find the smallest sextalternadosextalternado number.

Answer, solutions and source

Problem 2

  • Day 1

Esmeralda has created a special knight to play on quadrilateral boards that are identical to chessboards. If a knight is in a square then it can move to another square by moving 1 square in one direction and 3 squares in a perpendicular direction (which is a diagonal of a 2×42\times4 rectangle instead of 2×32\times3 like in chess). In this movement, it doesn't land on the squares between the beginning square and the final square it lands on.

A trip of the length nn of the knight is a sequence of nn squares C1,C2,...,CnC1, C2, ..., Cn which are all distinct such that the knight starts at the C1C1 square and for each ii from 11 to n−1n-1 it can use the movement described before to go from the CiCi square to the C(i+1)C(i+1) .

Determine the greatest N∈NN \in \mathbb{N} such that there exists a path of the knight with length NN on a 5×55\times5 board.

Answer, solutions and source

Problem 3

  • Day 1

Let triangle ABCABC be an acute triangle with AB≠ACAB\neq AC . The bisector of BCBC intersects the lines ABAB and ACAC at points FF and EE , respectively. The circumcircle of triangle AEFAEF has center PP and intersects the circumcircle of triangle ABCABC at point DD with DD different to AA .

Prove that the line PDPD is tangent to the circumcircle of triangle ABCABC .

Answer, solutions and source

Day 2

Problem 4

  • Day 2

Let x1,x2,x3,x4,x5∈R+x_1, x_2, x_3, x_4, x_5\in\mathbb{R}^+ such that x12−x1x2+x22=x22−x2x3+x32=x32−x3x4+x42=x42−x4x5+x52=x52−x5x1+x12x_1^2-x_1x_2+x_2^2=x_2^2-x_2x_3+x_3^2=x_3^2-x_3x_4+x_4^2=x_4^2-x_4x_5+x_5^2=x_5^2-x_5x_1+x_1^2 Prove that x1=x2=x3=x4=x5x_1=x_2=x_3=x_4=x_5 .

Answer, solutions and source

Problem 5

  • Day 2

There are 3 lines r,sr, s and tt on a plane. The lines rr and ss intersect perpendicularly at point AA . the line tt intersects the line rr at point BB and the line ss at point CC . There exist exactly 4 circumferences on the plane that are simultaneously tangent to all those 3 lines.

Prove that the radius of one of those circumferences is equal to the sum of the radius of the other three circumferences.

Answer, solutions and source

Problem 6

  • Day 2

A positive integer nn is called omopeiroomopeiro if there exists nn non-zero integers that are not necessarily distinct such that 20212021 is the sum of the squares of those nn integers. For example, the number 22 is not an omopeiroomopeiro , because 20212021 is not a sum of two non-zero squares, but 20212021 is an omopeiroomopeiro , because 2021=12+12+⋯+122021=1^2+1^2+ \dots +1^2 , which is a sum of 20212021 squares of the number 11 .

Prove that there exist more than 1500 omopeiroomopeiro numbers.

Note: proving that there exist at least 500 omopeiroomopeiro numbers is worth 2 points.

Answer, solutions and source