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KURSCHAK 1952 Problem 3

    ABCABC is a triangle. The point A' lies on the side opposite to AA and BA′/BC=kBA'/BC = k , where 1/2<k<11/2 < k < 1 . Similarly, B′B' lies on the side opposite to BB with CB′/CA=kCB'/CA = k , and C′C' lies on the side opposite to CC with AC′/AB=kAC'/AB = k . Show that the perimeter of A′B′C′A'B'C' is less than kk times the perimeter of ABCABC .

    Dataset text AI-MO AoPS. Quoted with source.

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