olymmath

KMO 2017 Problem 6

    In a quadrilateral ABCDABCD , we have ∠ACB=∠ADB=90\angle ACB = \angle ADB = 90 and CD<BCCD < BC . Denote EE as the intersection of ACAC and BDBD , and let the perpendicular bisector of BDBD hit BCBC at FF . The circle with center FF which passes through BB hits ABAB at P(≠B)P (\neq B) and ACAC at QQ . Let MM be the midpoint of EPEP . Prove that the circumcircle of EPQEPQ is tangent to ABAB if and only if B,M,QB, M, Q are colinear.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator kr-kmo/2017/p6 · Tag N32P0ZRE4J · Edit this page on GitHub · Keys: j next, k previous