olymmath

KMO 2008 Problem 1

    Hexagon ABCDEFABCDEF is inscribed in a circle OO . Let BD∩CF=G,AC∩BE=H,AD∩CE=IBD \cap CF = G, AC \cap BE = H, AD \cap CE = I Following conditions are satisfied. BD⊥CF,CI=AIBD \perp CF , CI=AI Prove that CH=AH+DECH=AH+DE is equivalent to GH×BD=BC×DEGH \times BD = BC \times DE

    Dataset text AI-MO AoPS. Quoted with source.

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