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KMO 2002 Problem 1

    For a prime pp of the form 12k+112k+1 and Zp={0,1,2,⋯ ,p−1}\mathbb{Z}_p=\{0,1,2,\cdots,p-1\} , let Ep={(a,b)∣a,b∈Zp,p∤4a3+27b2}\mathbb{E}_p=\{(a,b) \mid a,b \in \mathbb{Z}_p, p\nmid 4a^3+27b^2\} For (a,b),(a′,b′)∈Ep(a,b), (a',b') \in \mathbb{E}_p we say that (a,b)(a,b) and (a′,b′)(a',b') are equivalent if there is a non zero element c∈Zpc\in \mathbb{Z}_p such that p∣(a′−ac4)p\mid (a' -ac^4) and p∣(b′−bc6)p\mid (b'-bc^6) . Find the maximal number of inequivalent elements in Ep\mathbb{E}_p .

    Dataset text AI-MO AoPS. Quoted with source.

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