olymmath

JBMO-SL 2016 G6

Given an acute triangle ABCA B C, erect triangles ABDA B D and ACEA C E externally, so that m(ADB^)=m(AEC^)=90∘m(\widehat{A D B})=m(\widehat{A E C})=90^{\circ} and BAD^≡CAE^\widehat{B A D} \equiv \widehat{C A E}. Let A1∈BC,B1∈ACA_{1} \in B C, B_{1} \in A C and C1∈ABC_{1} \in A B be the feet of the altitudes of the triangle ABCA B C, and let KK and LL be the midpoints of [BC1]\left[B C_{1}\right] and [CB1]\left[C B_{1}\right], respectively. Prove that the circumcenters of the triangles AKL,A1B1C1A K L, A_{1} B_{1} C_{1} and DEA1D E A_{1} are collinear.

Dataset text NuminaMath olympiads. Quoted with source.

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