olymmath

JBMO-SL 2009 G2

  • Answer

In a right trapezoid ABCD(AB∥CD)A B C D(A B \| C D) the angle at vertex BB measures 75∘75^{\circ}. Point HH is the foot of the perpendicular from point AA to the line BCB C. If BH=DCB H=D C and AD+AH=8A D+A H=8, find the area of ABCDA B C D.

Dataset text NuminaMath olympiads. Quoted with source.

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