JBMO-SL 2006 Problem 2

Let $x,y,z$ be positive real numbers such that $x+2y+3z=\frac{11}{12}$ . Prove the inequality $6(3xy+4xz+2yz)+6x+3y+4z+72xyz\le \frac{107}{18}$ .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

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