olymmath

KöMaL 2018 C1476

    Prove that the inequality (y−6)23xy+x⋅y+3y≥4+x−4x−xy12\frac{{(y-6)}^2}{3xy}+x\cdot \frac{y+3}{y}\ge 4+x-\frac{4}{x}-\frac{xy}{12} holds for all positive xx and yy.

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