olymmath

ISL 2012 G6

    Let ABCA B C be a triangle with circumcenter OO and incenter II. The points D,ED, E and FF on the sides BC,CAB C, C A and ABA B respectively are such that BD+BF=CAB D+B F=C A and CD+CE=ABC D+C E=A B. The circumcircles of the triangles BFDB F D and CDEC D E intersect at P≠DP \neq D. Prove that OP=OIO P=O I.

    Dataset text NuminaMath olympiads. Quoted with source.

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