olymmath

ISL 1991 Problem 7

    ABCDABCD is a terahedron: AD+BD=AC+BC,AD+BD=AC+BC, BD+CD=BA+CA,BD+CD=BA+CA, CD+AD=CB+AB,CD+AD=CB+AB, M,N,PM,N,P are the mid points of BC,CA,AB.BC,CA,AB. OA=OB=OC=OD.OA=OB=OC=OD. Prove that ∠MOP=∠NOP=∠NOM.\angle MOP = \angle NOP =\angle NOM.

    Dataset text AI-MO AoPS. Quoted with source.

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