olymmath

IR-TST 2004 Problem 6

    pp is a polynomial with integer coefficients and for every natural nn we have p(n)>np(n)>n. xkx_k is a sequence that: x1=1,xi+1=p(xi)x_1=1, x_{i+1}=p(x_i) for every NN one of xix_i is divisible by N.N. Prove that p(x)=x+1p(x)=x+1

    Dataset text AoPS wiki problems. Quoted with source.

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