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IMC 2013 Problem 7

    Let p,q{p,q} be relatively prime positive integers. Prove that ∑k=0pq−1(−1)⌊kp⌋+⌊kq⌋={0 if pq is even1if pq odd{ \sum_{k=0}^{pq-1} (-1)^{\left\lfloor \frac{k}{p}\right\rfloor + \left\lfloor \frac{k}{q}\right\rfloor} = \begin{cases} 0 & \textnormal{ if } pq \textnormal{ is even} 1 & \textnormal{if } pq \textnormal{ odd}\end{cases}}

    Proposed by Alexander Bolbot, State University, Novosibirsk.

    Dataset text AI-MO AoPS. Quoted with source.

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