olymmath

KöMaL 2019 B5057

    Let DD and EE be points on leg BCBC of a right-angled triangle with hypotenuse ABAB such that ∠DAC=∠EAD=∠BAE\angle DAC = \angle EAD= \angle BAE. The feet of the perpendiculars dropped from vertex CC onto the line segment ADAD and from point DD onto the hypotenuse ABAB are FF and KK, respectively. Line CKCK intersects line segment AEAE at point HH, and the parallel line drawn from point HH to the line ADAD intersects line segment BCBC at point MM. Show that point FF is the circumcentre of triangle CHMCHM.

    Official text KöMaL. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator hu-komal/2019/b5057 · Tag HZP2C3RY8N · Edit this page on GitHub · Keys: j next, k previous