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CN-LEAGUE 2000 Problem 1

    In acute-angled triangle ABC,ABC, E,FE,F are on the side BC,BC, such that ∠BAE=∠CAF,\angle BAE=\angle CAF, and let M,NM,N be the projections of FF onto AB,AC,AB,AC, respectively. The line AEAE intersects ⊙(ABC)\odot (ABC) at DD (different from point AA ). Prove that SAMDN=S△ABC.S_{AMDN}=S_{\triangle ABC}.

    Dataset text AI-MO AoPS. Quoted with source.

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