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KöMaL 2016 B4801

    Define the sequence fnf_n of functions by the following recurrence relation: f0(x)=f1(x)=1, and for n≥2fn(x)=fn−1(x)⋅2cos⁡(2x)−fn−2(x).f_0(x) = f_1(x) = 1, \mathrm{~and ~for ~} n\ge 2 f_n(x) = f_{n-1}(x) \cdot 2\cos(2x) - f_{n-2}(x). Determine the number of roots of fn(x)f_n(x) in the interval [0,π][0,\pi].

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