olymmath

KöMaL 2010 B4236

    Let aa , bb and cc be the sides of triangle ABCABC , let faf_a, fbf_b and fcf_c denote the lengths of the interior angle bisectors, and let tat_a, tbt_b and tct_c be the segments of the interior angle bisectors that lie inside the circumscribed circle. Show that a2b2c2=fafbfctatbtca^2b^2c^2= f_af_bf_ct_at_bt_c.

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