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TH-TMO 2009 Problem 8

    Let a,b,ca, b, c be side lengths of a triangle, and define s=a+b+c2s =\frac{a+b+c}{2} . Prove that 2a(2a−s)b+c+2b(2b−s)c+a+2c(2c−s)a+b≥s.\frac{2a(2a-s)}{b + c}+\frac{2b(2b - s)}{c + a}+\frac{2c(2c - s)}{a + b}\ge s.

    Dataset text AI-MO AoPS. Quoted with source.

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