olymmath

KöMaL 2006 C859

    Prove that the equality c2+2absin⁡(γ+30∘)=b2+2acsin⁡(β+30∘)=a2+2bcsin⁡(α+30∘).c^2+2ab\sin (\gamma+30^{\circ}) =b^2+2ac\sin (\beta+30^{\circ}) =a^2+2bc\sin (\alpha+30^{\circ}). holds in every triangle.

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