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KöMaL 2023 C1766

    Show that in every triangle (with conventional notations), asin⁡α+bsin⁡β+csin⁡γ=(a+b+c)(sin⁡α+sin⁡β+sin⁡γ).\sqrt{a\sin{\alpha}}+\sqrt{b\sin{\beta}}+\sqrt{c\sin{\gamma}}=\sqrt{(a+b+c)(\sin{\alpha}+\sin{\beta}+\sin{\gamma})}.

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