olymmath

KöMaL 2005 B3817

    The sequence ana_n is defined as follows: a1≠a_1 \ne2, a2=a1a1−2a_2=\frac{a_1}{a_1-2}, an+1=nan2nan2−(n+1)an+(n+1)a_{n+1}=\frac{na_n^2}{na_n^2-(n+1)a_n+(n+1)}, if n≥n \ge2. Prove that the inequality a1a_1+2a2a_2+3a3a_3+...+nanna_n=a1.a2.a3.....ana_1 ^. a_2 ^. a_3 ^. ...^. a_n is true for all nn.

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