olymmath

KöMaL 2007 B4049

    aa, bb, cc are positive real numbers, and ab+bc+ca=13ab+bc+ca=\frac{1}{3}. Prove that aa2−bc+1+bb2−ca+1+cc2−ab+1≥1a+b+c.\frac{a}{a^2-bc+1}+\frac{b}{b^2-ca+1}+\frac{c}{c^2-ab+1}\ge\frac{1}{a+b+c}.

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