olymmath

HMMT November 2022 U14

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Real numbers xx and yy satisfy the following equations:

x=log⁡10(10y−1+1)−1y=log⁡10(10x+1)−1\begin{aligned} x & =\log _{10}\left(10^{y-1}+1\right)-1 \\ y & =\log _{10}\left(10^{x}+1\right)-1 \end{aligned}

Compute 10x−y10^{x-y}.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{101}{110}

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