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HMMT November 2018 U35

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Pascal has a triangle. In the nnth row, there are n+1n+1 numbers an,0,an,1,an,2,…,an,na_{n, 0}, a_{n, 1}, a_{n, 2}, \ldots, a_{n, n} where an,0=an,n=1a_{n, 0}=a_{n, n}=1. For all 1≤k≤n−1,an,k=an−1,k−an−1,k−11 \leq k \leq n-1, a_{n, k}=a_{n-1, k}-a_{n-1, k-1}. Let NN be the value of the sum

∑k=02018∣a2018,k∣(2018k).\sum_{k=0}^{2018} \frac{\left|a_{2018, k}\right|}{\binom{2018}{k}} .

Estimate NN. An estimate of E>0E>0 earns ⌊20⋅2−∣N−E∣/70⌋\left\lfloor 20 \cdot 2^{-|N-E| / 70}\right\rfloor points.

Dataset text NuminaMath olympiads. Quoted with source.

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