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HMMT 2021 U34

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Let f(n)f(n) be the largest prime factor of nn. Estimate

N=⌊104⋅∑n=2106f(n2−1)∑n=2106f(n)⌋.N=\left\lfloor 10^{4} \cdot \frac{\sum_{n=2}^{10^{6}} f\left(n^{2}-1\right)}{\sum_{n=2}^{10^{6}} f(n)}\right\rfloor .

An estimate of EE will receive max⁡(0,⌊20−20(∣E−N∣103)1/3⌋)\max \left(0,\left\lfloor 20-20\left(\frac{|E-N|}{10^{3}}\right)^{1 / 3}\right\rfloor\right) points.

Dataset text NuminaMath olympiads. Quoted with source.

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