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HMMT November 2018 U17

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Pascal has a triangle. In the nnth row, there are n+1n+1 numbers an,0,an,1,an,2,…,an,na_{n, 0}, a_{n, 1}, a_{n, 2}, \ldots, a_{n, n} where an,0=an,n=1a_{n, 0}=a_{n, n}=1. For all 1≤k≤n−1,an,k=an−1,k−an−1,k−11 \leq k \leq n-1, a_{n, k}=a_{n-1, k}-a_{n-1, k-1}. What is the sum of the absolute values of all numbers in the 2018th row?

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{2^{2018}+2}{3}

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