olymmath

HMMT November 2018 T5

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Find the sum of all positive integers nn such that 1+2+⋯+n1+2+\cdots+n divides

15[(n+1)2+(n+2)2+⋯+(2n)2].15\left[(n+1)^{2}+(n+2)^{2}+\cdots+(2 n)^{2}\right] .

Dataset text NuminaMath olympiads. Quoted with source.

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