olymmath

HMMT November 2014 U24

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Let ABCA B C be a triangle with AB=13,BC=14A B=13, B C=14, and CA=15C A=15. We construct isosceles right triangle ACDA C D with ∠ADC=90∘\angle A D C=90^{\circ}, where D,BD, B are on the same side of line ACA C, and let lines ADA D and CBC B meet at FF. Similarly, we construct isosceles right triangle BCEB C E with ∠BEC=90∘\angle B E C=90^{\circ}, where E,AE, A are on the same side of line BCB C, and let lines BEB E and CAC A meet at GG. Find cos⁡∠AGF\cos \angle A G F.

Dataset text NuminaMath olympiads. Quoted with source.

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-\frac{5}{13}

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