olymmath

HMMT 2008 U18

  • Guts
  • Answer

Let ABCA B C be a right triangle with ∠A=90∘\angle A=90^{\circ}. Let DD be the midpoint of ABA B and let EE be a point on segment ACA C such that AD=AEA D=A E. Let BEB E meet CDC D at FF. If ∠BFC=135∘\angle B F C=135^{\circ}, determine BC/ABB C / A B.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{\sqrt{13}}{2}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2008/u18 · Tag 73ST60T0F3 · Edit this page on GitHub · Keys: j next, k previous