olymmath

HMMT November 2013 T9

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For an integer n≥0n \geq 0, let f(n)f(n) be the smallest possible value of ∣x+y∣|x+y|, where xx and yy are integers such that 3x−2y=n3 x-2 y=n. Evaluate f(0)+f(1)+f(2)+⋯+f(2013)f(0)+f(1)+f(2)+\cdots+f(2013).

Dataset text NuminaMath olympiads. Quoted with source.

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