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HMMT November 2013 T10

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Let ω=cos⁡2π727+isin⁡2π727\omega=\cos \frac{2 \pi}{727}+i \sin \frac{2 \pi}{727}. The imaginary part of the complex number

∏k=813(1+ω3k−1+ω2⋅3k−1)\prod_{k=8}^{13}\left(1+\omega^{3^{k-1}}+\omega^{2 \cdot 3^{k-1}}\right)

is equal to sin⁡α\sin \alpha for some angle α\alpha between −π2-\frac{\pi}{2} and π2\frac{\pi}{2}, inclusive. Find α\alpha.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{12 \pi}{727}

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