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HMMT November 2013 T6

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Points A,B,CA, B, C lie on a circle ω\omega such that BCB C is a diameter. ABA B is extended past BB to point B′B^{\prime} and ACA C is extended past CC to point C′C^{\prime} such that line B′C′B^{\prime} C^{\prime} is parallel to BCB C and tangent to ω\omega at point DD. If B′D=4B^{\prime} D=4 and C′D=6C^{\prime} D=6, compute BCB C.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{24}{5}

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