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BALTIC-WAY 2018 Problem 11

    The points A,B,C,DA, B, C, D lie, in this order, on a circle ω\omega, where ADA D is a diameter of ω\omega. Furthermore, AB=BC=aA B=B C=a and CD=cC D=c for some relatively prime integers aa and cc. Show that if the diameter dd of ω\omega is also an integer, then either dd or 2d2 d is a perfect square.

    Dataset text NuminaMath olympiads. Quoted with source.

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