olymmath

HMMT November 2012 E7

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Find the number of ordered 2012-tuples of integers (x1,x2,…,x2012)\left(x_{1}, x_{2}, \ldots, x_{2012}\right), with each integer between 0 and 2011 inclusive, such that the sum x1+2x2+3x3+⋯+2012x2012x_{1}+2 x_{2}+3 x_{3}+\cdots+2012 x_{2012} is divisible by 2012 .

Dataset text NuminaMath olympiads. Quoted with source.

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2012^{2011}

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