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HMMT November 2011 U21

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Let P(x)=x4+2x3−13x2−14x+24P(x)=x^{4}+2 x^{3}-13 x^{2}-14 x+24 be a polynomial with roots r1,r2,r3,r4r_{1}, r_{2}, r_{3}, r_{4}. Let QQ be the quartic polynomial with roots r12,r22,r32,r42r_{1}^{2}, r_{2}^{2}, r_{3}^{2}, r_{4}^{2}, such that the coefficient of the x4x^{4} term of QQ is 1 . Simplify the quotient Q(x2)/P(x)Q\left(x^{2}\right) / P(x), leaving your answer in terms of xx. (You may assume that xx is not equal to any of r1,r2,r3,r4)\left.r_{1}, r_{2}, r_{3}, r_{4}\right).

Dataset text NuminaMath olympiads. Quoted with source.

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x^{4}-2 x^{3}-13 x^{2}+14 x+24

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