olymmath

HMMT 2023 T8

  • Team
  • Answer

Find, with proof, all nonconstant polynomials P(x)P(x) with real coefficients such that, for all nonzero real numbers zz with P(z)≠0P(z) \neq 0 and P(1z)≠0P\left(\frac{1}{z}\right) \neq 0, we have

1P(z)+1P(1z)=z+1z\frac{1}{P(z)}+\frac{1}{P\left(\frac{1}{z}\right)}=z+\frac{1}{z}

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

P(x)=\frac{x\left(x^{4 k+2}+1\right)}{x^{2}+1} \text{ or } P(x)=\frac{x\left(1-x^{4 k}\right)}{x^{2}+1}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2023/t8 · Tag WDHXB2SMPE · Edit this page on GitHub · Keys: j next, k previous